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CGP EDU Academic Team
Published on: August 14, 2026
The tangent lines to the circle x² + y² − 6x + 4y = 12 which are parallel to the line 4x + 3y + 5 = 0 are given by:
Text Solution
Verified by ExpertsThe correct answer is:
B
Line parallel to given line 4x + 3y + 5 = 0 is 4x + 3y + k = 0
This is tangent to x 2 + y 2 – 6x + 4y – 12 = 0
= 5 ⇒ 6 + k = ±25 ⇒ k = 19, –31
Hence required line 4x + 3y – 31 = 0, 4x + 3y + 19 = 0
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